Asmall metal bead, labeled a, has a charge of 28 nc .it is touched to metal bead b, initially neutral, so that the two beads share the 28 nc charge, but not necessarily equally. when the two beads are then placed 5.0 cmapart, the force between them is 4.8×10^−4 n . assume that a has a greater charge. what is the charge qa and qb on the beads?

Explanation:

Let the charge on bead A be q nC  and the charge on bead B be 28nC - qnC

Force F between them

4.8\times10^{-4} =

=120 x 10⁻⁸ = 9 x q(28 - q ) x 10⁻⁹

133.33 = 28q - q²

q²- 28q +133.33 = 0

It is a quadratic equation , which has two solution

q_A = 21.91 x 10⁻⁹C or q_B = 6.09 x 10⁻⁹ C

it would be a very light gray or not there at all antartica very rarely gets sun. so it would be hard to see your shadow. hope this ! (sorry if it dosn't)

explanation:

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.