Atest specimen in a tensile test has a gage length of 2.0 in and an area = 0.5in^2. during the test the specimen yields under a load of 32,000 lb. the corresponding gage length = 2.0083 in. this is the 0.2% yield point. the maximum load of 60,000 lb is reached at a gage length = 2.6 in. determine a) yield strength, b) madulus of elasticity, and c) ten

yield strength is 64000 lb/ in²

modulus of elasticity is 29.76 × lb/in²

Explanation:

given data

length L = 2 in

area A = 0.5 in²

load = 32000 lb

gage length L1 = 2.0083 in

yield point = 0.2%

maximum load = 60000 lb

to find out

yield strength and modulus of elasticity

solution

we apply here yield strength that is express as

yield strength =  ...........1

yield strength =  

yield strength = 64000 lb/ in²

and

modulus of elasticity  is calculated as

modulus of elasticity =      ..........2

here strain =  

strain =  

strain = 0.00415

so new strain after offset is here 0.00415 - 0.002

new strain = 0.00215

so from equation 2

modulus of elasticity =    

modulus of elasticity =    

modulus of elasticity is 29.76 × lb/in²

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

an obstruction