Two children on opposite sides of a 13 kg door (i = 1/3 ml 2 ) apply a force to the door. the first child pushes with force f at an angle of 80° relative to the door at a position r 1 from the door’s hinges. the second child pushes with a force of 15 n perpendicular to the door at a position 0.3 m from the door’s hinges. the width of the door is 0.4 m. what is the door’s angular acceleration?

γ = 1.42 * F1 * r1 - 6.52 Nm

Explanation:

The first kid will apply a torque of:

T = F * d * sin(a)

T1 = F1 * r1 * sin(80)

T1 = 0.98 * F1 * r1

The second kid applies a torque of

T2 = -15 * 0.3 * sin(90) = -4.5 Nm (negative because it is in the opposite direction as the other kid)

The angular momentum of the door is:

I = 1/3 * m * L^2

I = 1/3 * 13 * 0.4^2 = 0.69 kg*m^2

The total torque applied is:

T = T1 + T2

T = 0.98 * F1 * r1 - 4.5 Nm

The angular acceleration will be:

γ = T / I

γ = (0.98 * F1 * r1 - 4.5) / 0.69

γ = 1.42 * F1 * r1 - 6.52 Nm

what question you dont ask a question

explanation:

note: the given question is incomplete.

complete question is given below.

which is an example of kinetic energy?

a. the energy stored in ethanol  

b. a hockey puck sliding across the ice  

c. a compressed spring  

d. a ball sitting at the top of a ramp

solution: the kinetic energy is the energy posses by the virtue of the motion of the object.

in the given options, a, c and d are the example of potential energy because it is the energy posses by the virtue of the rest of the object. but option b has the kinetic energy as the object is in motion.

hence, a hockey puck sliding across the ice   is the apex example of kinetic energy.

so, the option (b) a hockey puck sliding across the ice   is the correct option.