In some cases, neither of the two equations in the system will contain a variable with a coefficient of 1, so we must take a further step to isolate it. let's say we now have
3c+4d=5
2c+5d=2
none of these terms has a coefficient of 1. instead, we'll pick the variable with the smallest coefficient and isolate it. move the term with the lowest coefficient so that it's alone on one side of its equation, then divide by the coefficient. which of the following expressions would result from that process?
c=53−43d
c=1−52d
d=25−25c
d=54−34c
submitmy answersgive up
correct
part e - solving for two variables
now that you have one of the two variables in part d isolated, use substitution to solve for the two variables. you may want to review the multiplication and division of fractions and simplifying an expression primers.
enter the answer as two numbers (either fraction or decimal), separated by a comma, with c first.
need the answer with work shown for part e.
in advance

Part f - example: finding two forces (part i) two dimensional dynamics often involves solving for two unknown quantities in two separate equations describing the total force. the block in (figure 1) has a mass m=10kg and is being pulled by a force f on a table with coefficient of static friction îľs=0.3. four forces act on it: the applied force f (directed î¸=30â above the horizontal). the force of gravity fg=mg (directly down, where g=9.8m/s2). the normal force n (directly up). the force of static friction fs (directly left, opposing any potential motion). if we want to find the size of the force necessary to just barely overcome static friction (in which case fs=îľsn), we use the condition that the sum of the forces in both directions must be 0. using some basic trigonometry, we can write this condition out for the forces in both the horizontal and vertical directions, respectively, as: fcosî¸â’îľsn=0 fsinî¸+nâ’mg=0 in order to find the magnitude of force f, we have to solve a system of two equations with both f and the normal force n unknown. use the methods we have learned to find an expression for f in terms of m, g, î¸, and îľs (no n).

While you are driving in the lane next to the curb on a multi-lane road the car on your left suddenly moves toward you lane. they are about toy crash into your front fender. you

Where is the potential energy throughout the loading, cocking, and releasing of the trebuchet?