Two electrons in a vacuum exert force of f = 3.8e-09 n on each other. they are then moved such that they are separated by x = 8.2 times their original distance. what is the force that the electrons experience at the new distance, f_n, in newtons? numeric: a numeric value is expected and not an expression. f_n = how far apart were the electrons originally in meters? numeric: a numeric value is expected and not an expression. d =

F_n = 5.65E-11 N

d =  1.20682E-31 m

Explanation:

F = 3.8E-09 N

where

m = Mass of electron = 9.109E−31 kilograms

G = Gravitational constant = 6.67E-11 m³/kgs²

x = Distance between them

For

Dividing the above equations we get

F_n = 5.65E-11 N

d =  1.20682E-31 m

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation:

did yall get answers for this yet