Aswimmer bounces straight up from a diving board and falls feet first into a pool. she starts with a velocity of 4.00 m/s and her takeoff point is 1.80 m above the pool. (a) how long are her feet in the air? � (b) what is the highest point above the board her feet reach? (c) what is her velocity when her feet hit the water?

Explanation:

Given that,

Velocity = 4.00 m/s

Distance = 1.80 m

(a). We need to calculate the time

Using equation of motion

Put the value in the equation

The time is 1.139 sec.

(b). We need to calculate the highest point above the board her feet reach

Using equation of motion

Put the value in the equation

The highest point above the board her feet reach is

The highest point above the board her feet reach is 2.62 m

(c). We need to calculate her velocity when her feet hit the water

Using equation of motion

Put the value in the equation

Her velocity when her feet hit the water is 7.16 in downward.

Hence, This is the required solution.

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.