Physics, 06.09.2019 19:30 nylaboo2222

My notes ask your the speed of light is now defined to be c= 2.99792458*101 mis. (a) express the speed of light to three significant figures. m/s (b) express the speed of light to five significant figures. m/s (c) express the speed of light to seven significant figures. m/s

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Answer from: brooklynunderwood46

Answer :

(a) The speed of light in three significant figures is, $3.00\times 10^1m/s$

(b) The speed of light in five significant figures is, $2.9979\times 10^1m/s$

Explanation :

Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

As we are given that the speed of light is:

$2.99792458\times 10^1m/s$

In the given value, there are 9 significant figures.

(a) Now we have to determine the speed of light in three significant figures.

For three significant figure, we round off the digits and we get:

$3.00\times 10^1m/s$

(b) Now we have to determine the speed of light in five significant figures.

$2.9979\times 10^1m/s$

$2.997924\times 10^1m/s$

Answer from: Quest

most voltage drop calculators want the distance between the source and destination. then internally, they double it so both the source and return wires are calculated. but you need to know which distance the calculator uses so you're not half of what you should be or double what you should be.

most circuit breakers will not take a #6 directly, so the electrician will have to splice on a smaller pigtail. you also have to upsize the grounding wire when you upsized the ungrounded (hot) wire (see note in 250.122). this will preclude using most cable assemblies, as a cable with #6 copper will most likely only have a #10 grounding conductor. you need a #6 grounding conductor if the circuit is 20a. a #8 cable is no better, as it will have a #10 grounding conductor too. but most 20a breakers will take a #8 directly.

in your related post, you didn't say what type of load this is. if it is a light or heater, voltage drop won't be a big issue. if this is a motor, the current needs are huge at startup and the voltage drop can pose a problem. if this is a motor, knowing if the motor is under much load during startup will answer the voltage drop effect (a saw is easier to start than a compressor).

Answer from: Quest

Ithink the answer is d i hope it my friend message me if i’m wrong and i’ll change my answer and fix it for you

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My notes ask your the speed of light is now defined to be c= 2.99792458*101 mis. (a) express the spe...