On the apollo 14 mission to the moon, astronaut alan shepard hit a golf ball with a golf club improvised from a tool. the free-fall acceleration on the moon is 1/6 of its value on carth. suppose he hit the ball with a speed of 25 m/s at an angle 30° above the horizontal. a. how long was the ball in flight? b. how far did it travel? c. ignoring air resistance, how much farther would it travel on the moon than on earth?

15 s

32. 1 m

1/6 times

Explanation:

Thinking process:

The acceleration due to gravity =

                                                     = 1.635 m/s²

Solving for the distance gives

s  = ut - 1/2at²

  =  33.1 m

Time taken will be:

The distance traveled = vt

                                      =

Therefore, distance traveled on the surface =

the answer is a 3.8cm

explanation:

as we know our atmosphere or air have different levels. every level has other gasses, and every gas has another permeability. when the light comes from lower permeability to higher permeability, it changes its direction. so that means that when the light comes from the moon to the earth, it changes it's direction many more times. it basically means that the shape of the light part of the moon is changed on the earth.

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