Aparachutist bails out and freely falls 62 m. then the parachute opens, and thereafter she decelerates at 2.5 m/s2. she reaches the ground with a speed of 2.8 m/s. (a) how long is the parachutist in the air

16.4 s

Explanation:

For AB

initial velocity, u = 0

final velocity, v = ?

acceleration, a = 9.8 m/s^2

distance, s = 62 m

Let the time taken is t.

Use second equation of motion

t = 3.56 s

Use first equation of motion

v = u + at

v = 0 - 9.8 x 3.56

v = - 34.89 m/s

For BC

Let the time taken is t'

initial velocity, v = 34.89 m/s

final velocity, v' = 2.8 m/s

a = 2.5 m/s^2

use first equation of motion

v' = v + a t'

2.8 = 34.89 - 2.5 t'

t' = 12.84 s

So, the total time taken

T = t + t' = 3.56 + 12.84 = 16.4 s

the higher the current the higher the mag field around it the higher the influence on the compass

this is an example of "committed" time.

committed time, as contracted time, takes need over essential and available time since it is seen as profitable work. it alludes to the time allotted to keep up a home and family. at the point when a man is commuting using committed time this individual may feel that the drive is an obligation to family, for example, strolling youngsters to class or driving a mate to work. contracted and committed time clients may feel that their commute could really compare to the commute of important or leisure time clients on the grounds that their commute is profitable work. in this manner, they might be more disposed to pick a mechanized method of movement.