The electron gun in a television tube is used to accelerate electrons with mass 9.109 × 10−31 kg from rest to 3 × 107 m/s within a distance of 6.3 cm. assuming the electric field is constant, what electric field is required in the tube? the fundamental charge is qe .

Electric field, E = 40608.75 N/C

Explanation:

It is given that,

Mass of electrons,

Initial speed of electron, u = 0

Final speed of electrons,

Distance traveled, s = 6.3 cm = 0.063 m

Firstly, we will find the acceleration of the electron using third equation of motion as :

Now we will find the electric field required in the tube as :

E = 40608.75 N/C

So, the electric field required in the tube is 40608.75 N/C. Hence, this is the required solution.

the answer is d. 4

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