Acyclist maintains a constant velocity of 6.1 m/s headed away from point a. at some initial time, the cyclist is 242 m from point a. what will be his displacement from his starting position after 51 s? answer in units of m.

553.1m

Explanation:

When an object moves at constant velocity we can express this movement like V=x/t, where V is the velocity, x is the displacement and t is the time spent on it.

In that way, the expression x=V.t give us the displacement from t=0s until t=51s, but we have to sum the initial distance from the point A.

x=242m +V.t = 242m + (6.1m/s x 51s) = 553.1m

prolly a beacuse the momentuem the car has increases while going down hill

the temperature and the pressure affect solubility. temperature affects by changing the properties of the solvent. the increase in pressure increases solubility, the decrease in pressure decreases solubility.