The barrel of a rifle has a length of 0.89 m. a bullet leaves the muzzle of a rifle with a speed of 620 m/s. what is the acceleration of the bullet while in the barrel? a bullet in a rifle barrel does not have constant acceleration, but constant acceleration is to be assumed for this problem.

215955.06 m/s^2

Explanation:

length of barrel, s = 0.89 m

initial velocity of the bullet, u = 0 m/s

Final velocity of the bullet, v = 620 m/s

Let a be the acceleration of the bullet in the barrel

Use third equation of motion, we get

a = 215955.06 m/s^2

Thus, the acceleration of the bullet inside the barrel is  215955.06 m/s^2.

think about the oscillation of the toy shown in the video. when the toy is at the highest point of its motion, its velocity is zero and its acceleration is negative.

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2