Afuse in an electric circuit is a wire that is designed to melt, and thereby open the circuit, if the current exceeds a predetermined value. suppose that the material to be used in a fuse melts when the current density rises to 350 a/cm2. what diameter of cylindrical wire should be used to make a fuse that will limit the current to 0.58 a?

0.04594 cm

Explanation:

So, we need the wire melt when the max current density its . Now, we got our limit current, 0.58 A.

The current density its , so, with our data, we can obtain the cross area of the wire.

For a cylinder, the area its given by:

We can put all this in the equation for the max current density:

And now, we can work it a little:

using our values, max current density = ,   and limit current = 0.58 A,

And, of course, the diameter its two times the radius:

15.3 cos 65 degrees trig

unlike poles attract