Aball is hung from a rope, making a pendulum. when it is pulled 5° to the side, the restoring force is 1.0 n. what will be the magnitude of the restoring force if the ball is pulled 10° to the side?

restoring force is 2 N

Explanation:

given data

angle pulled = 5°

force = 1 N

pulled = 10°

to find out

restoring force

solution

we know here force

force = m×g×sinθ     1

so here θ is very small so sinθ  = θ

1 = mg(5)

mg = 1 /5     2

and

now for 10 degree

we know here θ is small so sinθ  = θ

so from equation 1

force = m×g×sinθ

put equation 2 here

force = 1/5 × 10  

force = 2 N

so restoring force is 2 N

what is the question because that is not a question.