Aconcave mirror has a focal length of 30.0 cm. the distance between an object and its image is 45.0 cm. find the object and image dis- tances, assuming that (a) the object lies beyond the center of curvature and (b) the object lies between the focal point and the mirror.

object and image distances when object lies beyond center of curvature is 90 cm

object and image distances when object lies between focal point and mirror is 15 cm

Explanation:

given data

focal length f = 30.0 cm

distance between object and image = 45.0 cm

to find out

object and image distances

solution

we will apply here lens formula that is

(1/v) + (1/u) = (1/f)   1

and here v - u = 45

so v = 45 + u       2

so from equation 1

(1/(45+u)) + (1/u) = (1/30)

solve it we get u

u = 45 cm or -30 cm

so from equation 2

v = 45 + u

v = 45 + 45

v = 90 cm

object and image distances when object lies beyond center of curvature is 90 cm

and

v = 45 -30

v = 15 cm

object and image distances when object lies between focal point and mirror is 15 cm

no sign of dia of fuel cell

the answer is ampere

the ampere is used to measure electricity. an ampere is a unit of electric current equal. a unit of measure for the flow of current in a circuit. one ampere is the amount of current flow provided when one volt of electrical pressure is applied against one ohm of resistance.