Unpolarized light of intensity i=10 falls on two successive polarizer wheels with the angle between the polarizer wheels e-60°. what is the resultant intensity of the polarized light after leaving the 2nd polarizer? a) (0)/2 b) (10)/4 c) (0)/8 d) (o)/16

Explanation:

A polarizer changes the orientation of the oscillations of a light wave.

I₀ = Intensity of unpolarized light = 10

θ = Angle given to the polarizer = 60°

Intensity of light

I = I₀cos²θ

⇒I = 10cos²60

So, the after passing through the second polarizer is

the answer would be a

v=ir = 3x15 =45 v