Apractical rule is that a radioactive nuclide is essentially gone after 10 half-lives. what percentage of the original radioactive nuclide is left after 10 half-lives? how long will it take for 10 half-lives to pass for plutonium-239?

Explanation:

The equation for radioactive decay its:

,

where N(t) its quantity of material at time t, its the initial quantity of material and its the mean lifetime of the radioactive element.

The half-life its the time at which the quantity of material its the half of the initial value, so, we can find:

so:

So, after 10 half-lives, we got:

So, we got that a 0.09 % of the original radioactive nucllde its left.

Putonioum-239 has a half-life of 24,110 years. So, 10 half-life will take to pass

It will take 241,100 years for 10 half-lives of plutonium-239 to pass.

percentage left = 10 %

241 000 years

Explanation:

The half life, of plutonium-239 is 24 100 years.

Thus, the number of half lives that result in the decrease of the nucleotide is given by the following equation:

The percentage left will be 10 %

if , then after 10 half-life, the decay will be:

magnitude and direction

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