A14.0 gauge copper wire of diameter 1.628 mmcarries a current of 14.0 ma. part a: what is the potential difference across a 2.15 mlength of the wire?
part b: what would the potential difference in part a be if the wire were silver instead of copper, but all else was the same?

for copper potential difference is 2.4871 × V

for silver  potential difference is 2.1256 × V

Explanation:

given data

diameter D = 1.628 mm = 0.001628 m

current = 14.0 mA = 0.0140 A

length L = 2.15 m

to find out

potential difference

solution

we consider here

resistivity of silver =  1.47 × ohm-m

resistivity of copper = 1.72 × ohm-m

so we apply here resistance formula that is

Resistance = ρ × L / A     ...............1

so here area A = πr² = π(0.001628 /2)² = 2.0816 ×   m²

for copper Resistance = ρ × L / A

Resistance = 1.72 ×  × 2.15 / 2.0816 ×  

Resistance = 1.7765 ×  ohm

for silver Resistance = ρ × L / A

Resistance = 1.47 ×  × 2.15 / 2.0816 ×  

Resistance = 1.5183 ×  ohm

so

potential difference  is calculated as

for copper potential difference  = current × resistance

potential difference  = 0.0140 ×1.7765 ×

potential difference  = 2.4871 × V

for silver  potential difference  = current × resistance

potential difference  =  0.0140 × 1.5183 ×

potential difference  =  2.1256 × V

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation:

the answer is b, have negligible mass