Red blood cells often can be charged. two red blood cells are separated by 1.46 m and have an attractive electrostatic force of 0.965 n between them. if one of the red blood cells has a charge of +8.32 10-6 c, what is the sign and magnitude of the second charge

, negative charge

Explanation:

The magnitude of the electrostatic force between the two red blood cells is given by

where

k is the Coulomb's constant

q1 and q2 are the charges of the two cells

r is their separation

In this problem we know that

r = 1.46 m

Solving for q2, we find

And the force between the two cells is attractive, so since the first cell has positive charge, this second cell must have negative charge.

what was the answer?

e/c, where e is its total energy