An lc circuit has an inductance of 14 mh and a capacitance of 3.4 mf. if the charge amplitude is 52 mc, what is the current amplitude?

current amplitude is 31.03 A

Explanation:

given data

inductance L =14 mH

capacitance C = 3.4 mF = 3.4

charge amplitude q = 52 mC

to find out

current amplitude

solution

we will apply here formula for current that is

current = v    .............1

here v will calculate first

so we know q = c × v

put here value to find v

v = q/c = 52 ×  / 3.4 ×

v = 15.29 V

so from equation 1

current = 15.29  / 3.4 ×  }" alt="10^{-3}" />  / 3.4 ×  }" />

current = 31.03 A

so current amplitude is 31.03 A

low freq = 100 mhz

low wavelength =101.7m

length = 3x10^8/freq