Aconverging lens (f1 = 12.5 cm) is located 28.8 cm to the left of a diverging lens (f2 = -6.18 cm). a postage stamp is placed 36.9 cm to the left of the converging lens. locate the final image of the stamp relative to the diverging lens.

The final image relative to the diverging lens at 9.0 cm.

Explanation:

Given that,

Focal length of diverging lens = -6.18 cm

Focal length of converging lens = 12.5 cm

Distance of object = 36.9 cm

We need to calculate the image distance of converging lens

Using formula of lens

We need to calculate the image distance of diverging lens

Now, object distance is

Using formula of lens

The image is formed 9.0 cm to the left of the  diverging lens.

Hence, The final image relative to the diverging lens at 9.0 cm.

answer

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explanation: