An acrobat of mass ma jumps upwards off a trampoline with an initial speed v0. at a height h0, the acrobat grabs a clown of mass mb. assume that the time the acrobat takes to grab the clown is negligibly small. what is the maximum height hf reached by the acrobat and clown

Explanation:

Initial speed u = v₀

Final speed v at height h₀

v² = u² -2gh₀

v = \sqrt (v_0^2 -2gh_0)}

Applying conservation of momentum at height h₀

Velocity of combined mass upwards  V = m_A v / m_A+m_B

if H is the maximum height attained

H = V² /2g = m_A^2 (V_0^2-2gh_0) / 2g( m_A+m_B)^2

diagram is missing, but i will try to explain your doubt.

answer:

amplitude is the maximum displacement or distance moved on a point of a vibrating body or wave measured from its equilibrium position.it is equal to half the length of vibration path.

im sorry i dont know