Two long, straight, parallel wires are 10.0 cm apart and carry 4.80 a currents in the same direction. part a: find the direction of the magnetic field at point p1, midway between the wires
part b: find the magnitude of the magnetic field at point p1, midway between the wires.
part c: find the direction of the magnetic field at point p2, 28.0 cm to the right of p1.
part d: find the magnitude of the magnetic field at point p2, 28.0 cm to the right of p1.

5.9 x 10⁻⁶ T

Explanation:

The direction of magnetic field is clockwise around a long current carrying wire. Its value is given by the relation

B = Kx 2 current / distance [ K is a constant having value 10⁻⁷ for air.]

At the middle point between two given wires , magnetic field due to each of the wires will be equal and opposite.So they will cancel out each other to zero. Hence resultant magnetic field at this point will be zero.

Part C : At this point , magnetic field due to each of the wires will be added up because they act in the same direction.

Magnetic field due to first wire

B₁ =

= 3.4 x 10⁻⁶ T

Magnetic field due to second wire

B₂ =  

= 2.5 X 10⁻⁶ T

Total field = ( 3.4 +2.5)x 10⁻⁶

= 5.9 x 10⁻⁶ T.

Its direction will be downwards on the plane of the paper.

answer: a ball

explanation: because it will bounce

f is prop to m1xm2 double m1 double force