What is the mass of a baseball if the kinetic energy is 140 j when the baseball is thrown at 96 mph? 0.021 g a batter hits a pop fly, and the baseball reaches an altitude of 270 ft. if we assume that the ball was 3 ft. above home plate when hit by the batter, what is the ball's increase in potential energy? j

Explanation:

It is given that,

Kinetic energy of the baseball, E = 140 J

Speed with which the baseball is thrown, v = 96 mph = 42.91 m/s

(a) The kinetic energy of the ball is given by the formula as :

m = 0.15 kg

(b) The ball reaches a height, h = 270 ft = 82.29 m

The assumed height of the ball, h' = 3 ft = 0.914 m

The increase in potential energy of the ball is :

So, the increase in potential energy of the ball is 119.62 Joules. Hence, this is the required solution.

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm

it is b. absorbs thermal energy