1380 kg car is moving due east with an initial speed of 27.0 m/s. after 8.00 s the car had showd dwn to 17.0 m/s. find the magnitude and direction of the net force that produces the deceleration

magnitude of force is 1725 N

direction is opposite to the direction of car moving  i.e west

Explanation:

Given data

car mass = 1380 kg

speed = 27.0 m/s

time = 8 s

speed = 17 m/s

to find out

magnitude and direction of the net force

solution

we find here first acceleration thats formula is

a = v(initial) - v(final) / time

a =27 - 17 / 8

acceleration = 1.25 m/s

so force is = ma

force is = 1380 ( 1.25)

force = 1725 N

so magnitude of force is 1725 N

and this is here direction is opposite to the direction of car moving  i.e west

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