On a ride called the detonator at worlds of fun in kansas city, passengers accelerate straight downward from rest to 45 mi/h in 2.2 seconds. what is the average acceleration of the passengers on this ride?

Explanation:

It is given that,

Initial velocity of passengers, u =0

Final velocity of passengers, v = 45 mi/h = 20.11 m/s

Time taken, t = 2.2 s

We need to find the acceleration of the passengers on this ride. It can be calculated using the formula of acceleration as :

So, the acceleration of the passengers on this ride is . Hence, this is the required solution.

hi there!

out of the two, (b) precision would be more reasonable.   however, both a and b could be pretty reasonable.

-awesomerepublic   : )

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min