Apilot in a helicopter sights an ambulance heading toward an accident scene. he measures the angles of depression to the ambulance and the accident to be 21o and 15o, respectively. if the helicopter is 4000 ft from the ambulance, how far does the ambulance have to travel to get to the accident?

the ambulance have to travel 4507.847 feet to get to the accident

Explanation:

Let D represent position of ambulance

Let C represent position of accident scene

The situation is represented in the below attached figure

In the figure we have

AB = 4000 feet

Thus in triangle ABC we have

In triangle ABD we have

Thus the distance between the ambulance and accident scene will be 14925.20-10420.356 = 4507.847 feet

An  atom  (ours, not carroll's) consists of a positively charged  nucleus, surrounded by one or more negatively charged particles called  electrons. the positive charges equal the negative charges, so the atom has no overall charge; it is electrically neutral. most of an atom's mass is in its nucleus; the mass of an electron is only 1/1836 the mass of the lightest nucleus, that of hydrogen. although the nucleus is heavy, it is quite small compared with the overall size of an atom. the radius of a typical atom is around 0.1 to 0.25 nanometres (nm), whereas the radius of a nucleus is about 10-6  nm.  *  if an atom were enlarged to the size of the earth, its nucleus would be only 200 feet in diameter and could easily rest inside a small football stadium.read more on -