Calculate: ken is a bicyclist. he is moving from point c to point d up a hill. his starting velocity is 8m/s east and 1 second later, his final velocity is at 7m/s east. what is his average acceleration? hint: use the acceleration formula. a. 1 m/s^2. b. 7.5 m/s^2east. c. -1m/s^2 east. d. 10 m/s^2east.

C. -1m/s² east

Explanation:

starting velocity u= 8m/s

final velocity  v=7m/s

time t=1second

we know,

average acceleration=(v-u)/t

                                   ={ (7-8)/1 } m/s²

                                   =(-1/1 ) m/s²

                                    =-1 m/s²

the result is negative because his  final velocity is less than  starting velocity. That means there will be deceleration instead of acceleration.