Amagnesium surface has a work function of 3.60 ev. electromagnetic waves with a wavelength of 320 nm strike the surface and eject electrons. find the maximum kinetic energy of the ejected electrons. express your answer in electron volts.

K(maximum) = 0.284 eV

Explanation:

Given data

work function ω = 3.60 eV = 3.60 × 1.6 × = 5.76 × J

wavelength λ = 320 nm  = 320 × m

to find out

maximum kinetic energy

solution

we know that speed of light is =  3 × m/s

and planck constant h = 6.63 × J.s

we will apply here Einstein's photo elecric equation that is

hc/λ  =  ω + K(maximum)

put here all these value we get

6.63 × ×  3 ×  / 320 × =   5.76 ×  + K(maximum)

so

K(maximum) = 6.63 × ×  3 ×  / 320 × - 5.76 ×

K(maximum) = 0.4556 ×  J

K(maximum) = 0.4556 ×  / 1.6  ×

K(maximum) = 0.284 eV

emily ruth's annual premium is $1058.50

step-by-step explanation:

emily ruth is a female of 27 years age purchasing 20 year endowment insurance with face value $25000.

from the given table,

for females, the age of a male 3 years younger should be used.

so, we have to check for 24 year male for 20 year endowment.

it is 42.34 for every $1000 face value.

for a face value of $25000,

it is 25 * 42.34 = $1058.50

∴ emily ruth's annual premium is $1058.50

the answer is 3.1 his answer is wrong mines is right