Find the range in nanometers of visible wavelengths of light in zircon (n = 1.923). (assume visible light has wavelengths ranging from 380 nm to 760 nm in a vacuum.) shortest wavelength nm
longest wavelength nm

Explanation:

It is given that,

Refractive index of zircon, n = 1.923

The wavelength of visible light ranging from 380 nm to 760 nm in a vacuum.

Wavelength 1,

Wavelength 2,

We need to find the shortest and longest wavelength. For shortest wavelength,

For longest wavelength,  

Hence, this is the required solution.