Acar is traveling to the right with a speed of 29m/s when the rider slams on the accelerator to pass another car. the car passes in 110m with constant acceleration and reaches a speed of 34m/s. what was the acceleration of the car as it sped up? answer using a coordinate system where rightward is positive. round the answer to two significant digits.

A car s traveling to the right with a speed of 29m/s when it accelerates at 1.4 m/s² for 110 m to reach a speed of 34 m/s.

A car is moving with an initial speed (u) of 29 m/s. After displacing for 110 m (s) with a constant acceleration (a), it reaches a speed of 34 m/s (final speed = v).

We can calculate the magnitude of the acceleration of the car using the following kinematic equation.

A car s traveling to the right with a speed of 29m/s when it accelerates at 1.4 m/s² for 110 m to reach a speed of 34 m/s.

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Acceleration of the car is .

Explanation:

It is given that,

Initial speed of the car, u = 29 m/s

Finally it reaches a speed of, v = 34 m/s

Distance, d = 110 m

We need to find the acceleration of the car as it speed up. It can be calculated using third law of motion as :

So, the acceleration of the car as it speeds up is . Hence, this is the required solution.

another example of kinetic energy would be,

kinetic energy   >     moving energy

answer   >   letter choice (c),   a hammer falling off a table.

hope that !                                         : )