Consider a free particle moving in one dimension (a) write down the stationary schrödinger equation for the particle. (b) bearing in mind that the particle's energy must be positive, verify that the solution of the stationary schrödinger equation is of the form 6(x) = a sin(kx) + b cos(kx) and determine k in terms of eand m. (c) verify by substitution into the stationary schrödinger equation that (1) = cei + deika is also a solution, with the same k. determine c and d in terms of a and b.

Iam pretty sure its b but if im wrong sorry

It's because 3 if it was 10 it wouldn't look right do it goes up to 4d

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j