Acapacitor is connected to an ac power supply. the maximum current is 4.0 a and the reactance of the capacitor is xc = 8.0 ω. what is the average power dissipated by the capacitor? select one: a. 32 w b.0 w c. 128 w d. 64 w

option (b)

Explanation:

Io = 4 A

Xc = 8 ohm

The formula for the average power dissipated is given by

P = Vrms x Irms x cos Ф

Where, Ф be the phase difference between Vrms and Irms .

As we know that in case of capacitor, the current leads the voltage by 90 degree, it means the value of Ф is 90 degree.

Thus, Average power = Vrms x Irms x Cos 90

Average power = 0 Watt

you can cut your hand off if your not

you get 2.3=1.21*\frac{a}2 or 4.6=1.21a or a=3.802 (b)

explanation: