Apower source for a portable electrical defibrillator contains a capacitor of capacitance 60 μf. the potential difference across the plates of the capacitor is raised to 5.0x10^3 v and 20% of its stored energy is released in a 3.0 ms pulse. calculate the average power of the pulse.

Explanation:

Energy of the capacitor = 1/2 C V² = 1/2 X 60 X 10⁻⁶ X 5 X 10³ = 0.15 J

20 % = .03 J

Power = energy released per second = Energy / time = .03 /(3 x 10⁻³) = 10 W.

depends on what you mean by "group." for order, it would be coleoptera (beetles). for class, it would be insecta (insects). for phylum, it would be the arthropoda (animals with jointed exoskeletons).

explanation:

when it gains or loses electrons