A500-gram mass is attached to a spring and executes simple harmonic motion with a period of 0.25 second. if the total energy of the system is 4j, find the force constant of the spring?

315.5 N/m

Explanation:

m = 500 g = 0.5 kg

T = 0.25 second

Total energy, E = 4 J

Let K be the spring constant.

The formula for the time period is given by

K = 315.5 N/m

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