Find the current through a loop needed to create a maximum torque of 9.00 mn. the loop has 50 square turns that are 15.0 cm on a side and is in a uniform 0.800-t magnetic field.

10 A

Explanation:

τ = Maximum torque of the loop = 9 mN

N = Number of turns in the loop = 50

a = side of the loop = 15 cm = 0.15 m

A = Area of the loop = a² = 0.15² = 0.0225 m²

B = magnitude of magnetic field = 0.800 T

i = magnitude of current in the loop

Maximum torque of the loop is given as

τ = N B i A

Inserting the values

9 = (50) (0.8) (0.0225) i

i = 10 A

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards

i think the answer is tomato juice? not entirely sure though