Aparticle moves with acceleration function a(t) = 5 + 4t - 2t^2. its initial velocity v(0) = 3 m/s and its initial displacement is s(0) = 10 m. find its position after 4 seconds.

Its position after 4 seconds is 62 meters.

Explanation:

It is given that,

The acceleration of the particle is given by equation :

Also,

At t = 0, . So, c = 3

Also, , s is the position

At t = 0, . So, c' = 10

At t = 4 s

s = 62 m

So, at t = 4 seconds the position of the particle is 62 meters. Hence, this is the required solution.

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