Suppose you are sitting, naked, on a steel bench with a temperature of 10°c. the only thing insulating the core of your body (temperature 37°c) is a layer of skin (the epidermis and dermis together are about 4 mm thick) and fat (varies from individual to individual, but a typical thickness on the buttocks and the back of the thighs might be 1.0 cm.) estimate the rate of heat loss by conduction under this circumstance.
i estimated the area of skin to be 1m^2 and i disregarded insulation from the skin. i used 0.21 w/mk as the thermal conductivity (k) of fat. i keep getting 567 w, but the answer on my instructor's powerpoint says 56.7 w. i'm not sure what i'm doing wrong (or if she has somehow made an error). any is much appreciated! : )

Acommon technique in analysis of scientific data is normalization. the purpose of normalizing data is to eliminate irrelevant constants that can obscure the salient features of the data. the goal of this experiment is to test the hypothesis that the flux of light decreases as the square of the distance from the source. in this case, the absolute value of the voltage measured by the photometer is irrelevant; only the relative value conveys useful information. suppose that in part 2.2.2 of the experiment, students obtain a signal value of 162 mv at a distance of 4 cm and a value of 86 mv at a distance of 5.7 cm. normalize the students' data to the value obtained at 4 cm. (divide the signal value by 162.) then calculate the theoretically expected (normalized) value at 5.7 cm.