Afrog is 80 cm in front of a lens whose focal length is +50 cm. another lens of focal length +20 cm, is 100 cm behind the first lens. where is the image of the frog located? is it real or virtual?

image location is at 12.5 cm distance from another lens

and image is real

Explanation:

given data

distance q = 80 cm

focal distance f = 50 cm

focal length  f2 = 20 cm

distance  = 100 cm

to find out

image of the frog located and  Is it real or virtual

solution

we apply here lens formula that is

1/f = 1/p + 1/ q

1/50 = 1/p + 1/80

p = 133.3 cm

so at another lens distance is  100 - 133.3

distance q = -33.3 cm

so lens formula

1/f = 1/p + 1/q

1/20 = -1/33.3 + 1/p

p = 12.5 cm

so image location is at 12.5 cm distance from another lens

and image is real

because growing process had stoped after 4-5 year

as we probably am aware that our atmosphere or air have various levels, each level has different gasses, and each gas has another porousness. at the point when the light originates from lower porousness to higher penetrability, it alters its course. with the goal that implies that when the light originates from the moon to the earth, it alters it's course a lot more occasions. it essentially implies that the state of the light piece of the moon is changed on the earth.

not copied too! hope this !

joke:

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