Ajet of water moving at 20 m/s impinges on a symmetrical curved vane shaped to deflect the jet through 120o (i. e. the blade angles β1 and β2 are both 30o ). if the vane is moving at 5 m/s, find the angle of the jet so that there is no shock at the inlet. also determine the absolute velocity of exit in magnitude and direction. also determine the work done.

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j

i dont have a visual in front of me, but i can you reason to try to get the right one. the graph should look like this, 0 to 6 there is a spike, 12 to 14 there should be a very low point. slight increase in the graph at 12 to 14, and flat 14 to 18

explanation: