Acircular loop of wire of radius r = 0.072 m is placed in a uniform magnetic field b = 13 t, with the plane of the loop perpendicular to the direction of the field, b . calculate the magnetic flux through the loop. 0.021 wb 0.293 wb 0.212 wb 0.179 wb

0.212 Wb

Explanation:

Area = π r² = π (0.072)² = 0.01628 m²

Magnetic field given = B = 13 T

Magnetic flux is the dot product of the Area of cross section and the magnetic field.

Magnetic flux is the number of field lines that pass through a given surface.

Ф = B.A cos θ here θ is the angle between the magnetic field lines and the normal perpendicular to the surface.

Ф = (13)(0.01628) =0.212 Wb  

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever