Example 3 in einstein's theory of special relativity the mass of an object moving with velocity v is m = m0 1 − v2/c2 where m0 is the mass of the object when at rest and c is the speed of light. the kinetic energy of the object is the difference between its total energy and its energy at rest: k = mc2 − m0c2. (a) show that when v is very small compared with c, this expression for k agrees with classical newtonian physics: k = 1 2 m0v2. (b) use taylor's inequality to estimate the difference in these expressions for k when |v| ≤ 50 m/s.

i'm thinking more like energy

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .

ya te mando la respuesta