The moment arm of the shoulder abductor muscles is approxi- mately 5 cm from the axis of rotation of the shoulder joint, and the force vector representing shoulder abductor muscle force is oriented at approximately 150° relative to the positive x-axis. the weight of the upper extremity of an 80-kg male is approximately 45 n. if the person is 1.78 m in height, then the center of gravity of the upper-extremity is approximately 0.25 m from the shoulder joint.
3. calculate the vertical component of the joint reaction force.
4. calculate the horizontal component of the joint reaction force.
5. calculate the orientation of the vector representing joint reaction force.

it breaks and dirupture other materials and other sencews from the bottom

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s