When landing after a spectacular somersault, a 40.5 kg gymnast decelerates by pushing straight down on the mat. calculate the force she must exert if her deceleration is 7.00 times the acceleration due to gravity in newtons.

F= = 3.18 * 10^3 N

Explanation:

information given:

m= 40.5 kg

a= seven times gravity so we have

a= 7 g

where

gravity = g  =9.8 m/s2

F= m*a

F= (40.5) * 7g

a = 7 g = (7) (9.8) = 68.6 m/s2

There are two forces acts on gymnsat

Where ,w is the weight of Gymnsat

F(net) = F - mg

F- mg = ma

F = mg+ma

so  

F=  m ( g + a)

F = (40.5) [9.8+ 68.6 ]

F = 3.18 * 10^3 N

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2