An electron is accelerated from rest through a potential difference of 4.55 kv. it enters a region where a uniform 4.4-mt magnetic field is perpendicular to the velocity of the electron. calculate the radius of the path this electron will follow in the magnetic field. (e = 1.60 x 10^-19 c, mass electron = 9.11 x 10^-31 kg)

Radius, r = 0.051 meters

Explanation:

It is given that,

Potential difference,

Magnetic field,

The magnetic field is perpendicular to the velocity of the electron. We need to calculate the radius of the path this electron will follow in the magnetic field.

The magnetic force is balanced by the centripetal force as:

..........(1)

Using the conservation of energy as :

Equation (1) becomes :

r = 0.051 m

So, the radius of the path this electron will follow in the magnetic field is 0.051 meters. Hence, this is the required solution.

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.

it would be c. predictability