The fusion reaction 2h + 2h --> 3he + n releases energy 3.27 mev per decay. how long could the fusion of 1.0 kg of this hydrogen isotope by this reaction keep a 100 w lamp burning?

time taken is  2.49  x year

Explanation:

Given data

energy = 3.27 MeV

mass = 1 kg

to find out

time period

solution

we know  that deuterium atomic mass unit = 1.66053886 x kg

and we know that energy release = 1 kg × 3.27 / 2×2×1.66053886 x

energy release = 4.9231 x MeV

energy release  = 4.9231 x  × 1.6 x  = 7.87 x  J

so at 100 W

energy = power × time

time = 7.87 x  / 100

time = 7.87 x s = 7.87 x  /  3.15 x =  2.49  x year

so time taken is  2.49  x year

heats surface water up