You wish to cool a 2.07 kg block of lead initially at 92.0°c to a temperature of 41.0°c by placing it in a container of olive oil initially at 24.0°c. determine the volume (in l) of the liquid needed in order to accomplish this task without boiling. the density and specific heat of olive oil are respectively 860 kg/m3 and 1,970 j/(kg · °c), and the specific heat of lead is 128 j/(kg · °c).

The volume of the olive oil is 0.468 L.

Explanation:

Given that,

Mass of lead m₁= 2.07 kg

Initial temperature of lead = 92.0°C

Initial temperature of oil = 41.0°C

Density of olive oil

Specific heat of lead

Specific heat of olive oil

We need to calculate the mass of the olive oil

The heat lost by the lead equal to the heat gained by olive oil

We need to calculate the volume of olive oil

Using formula of density of olive oil

Put the value into the formula

Hence, The volume of the olive oil is 0.468 L.