In a double-slit experiment, the third-order maximum for light of wavelength 520 nm is located 11 mm from the central bright spot on a screen 1.6 m from the slits. light of wavelength 650 nm is then projected through the same slits. how far from the central bright spot will the second-order maximum of this light be located?

far from the central bright spot is 9.16 mm

Explanation:

given data

wavelength  λ1 =  520 nm

distance y = 11 mm

screen  from the slits R  = 1.6 m

wavelength  λ2 =  650 nm

to find out

How far from the central bright spot

solution

we know the formula of distance from central bright spot that is

d = (m×λ×R) / y

here put all  value

m = 3 , λ1 = 520 × , R = 1.6 and y = 0.011

so

d = (3× 520 × × 1.6 ) / 0.011

so d = 226.90 × m

and

y = (m×λ×R) / d

here put all  value

m = 2 , λ2 = 650 × , R = 1.6 and d = 226.90×

so

y = (2× 650 × × 1.6 ) / 226.90×

so y = 9.16 × m

far from the central bright spot is 9.16 mm

c.the charges if the proton and electron and gravity

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm