Acircular loop of radius 11.7 cm is placed in a uniform magnetic field. (a) if the field is directed perpendicular to the plane of the loop and the magnetic flux through the loop is 8.60 10-3 t · m2, what is the strength of the magnetic field?

Magnetic field, B = 0.199 T

Explanation:

It is given that,

Radius of circular loop, r = 11.7 cm = 0.117 m

Magnetic flux through the loop,

The magnetic flux linked through the loop is :

Here,

or

B = 0.199 T

So, the strength of the magnetic field is 0.199 T. Hence, this is the required solution.

the answer is the first electromagnet (a). this is because it has more coils around the ferromagnetic material. increasing the number of coils increases the surface area in which the metal interacts with the current in the coil. this enables more atoms in the metal to become aligned hence becoming more magnetized.