If a basball is project upwards from the ground level with an initial velovaity of 32 feet per second, then it's height is a function of time.
given by s= -8t^2 + 32t. what is the maximum height reached by the ball?

Maximum height reached by the ball is 32 meters.

Explanation:

It is given that,

If a baseball is project upwards from the ground level with an initial velocity of 32 feet per second, then it's height is a function of time. The equation is given as :

...........(1)

t is the time taken

s is the height attained as a function of time.

Maximum height achieved can be calculated as :

-16 t + 32 = 0

t = 2 seconds

Put the value of t in equation (1) as :

s = 32 meters

So, the maximum height reached by the ball is 32 meters. Hence, this is the required solution.

the current is 0.6

voltage ÷ resistance = current

so 12 ÷ 20 = 0.6

ok

explanation: